\(\int \frac {1}{a+b \arccos (c x)} \, dx\) [160]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [F]
   Sympy [F]
   Maxima [F]
   Giac [A] (verification not implemented)
   Mupad [F(-1)]

Optimal result

Integrand size = 10, antiderivative size = 54 \[ \int \frac {1}{a+b \arccos (c x)} \, dx=\frac {\operatorname {CosIntegral}\left (\frac {a+b \arccos (c x)}{b}\right ) \sin \left (\frac {a}{b}\right )}{b c}-\frac {\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \arccos (c x)}{b}\right )}{b c} \]

[Out]

-cos(a/b)*Si((a+b*arccos(c*x))/b)/b/c+Ci((a+b*arccos(c*x))/b)*sin(a/b)/b/c

Rubi [A] (verified)

Time = 0.04 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {4720, 3384, 3380, 3383} \[ \int \frac {1}{a+b \arccos (c x)} \, dx=\frac {\sin \left (\frac {a}{b}\right ) \operatorname {CosIntegral}\left (\frac {a+b \arccos (c x)}{b}\right )}{b c}-\frac {\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \arccos (c x)}{b}\right )}{b c} \]

[In]

Int[(a + b*ArcCos[c*x])^(-1),x]

[Out]

(CosIntegral[(a + b*ArcCos[c*x])/b]*Sin[a/b])/(b*c) - (Cos[a/b]*SinIntegral[(a + b*ArcCos[c*x])/b])/(b*c)

Rule 3380

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[SinIntegral[e + f*x]/d, x] /; FreeQ[{c, d,
 e, f}, x] && EqQ[d*e - c*f, 0]

Rule 3383

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CosIntegral[e - Pi/2 + f*x]/d, x] /; FreeQ
[{c, d, e, f}, x] && EqQ[d*(e - Pi/2) - c*f, 0]

Rule 3384

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Dist[Cos[(d*e - c*f)/d], Int[Sin[c*(f/d) + f*x]
/(c + d*x), x], x] + Dist[Sin[(d*e - c*f)/d], Int[Cos[c*(f/d) + f*x]/(c + d*x), x], x] /; FreeQ[{c, d, e, f},
x] && NeQ[d*e - c*f, 0]

Rule 4720

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Dist[-(b*c)^(-1), Subst[Int[x^n*Sin[-a/b + x/b], x],
 x, a + b*ArcCos[c*x]], x] /; FreeQ[{a, b, c, n}, x]

Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {\sin \left (\frac {a}{b}-\frac {x}{b}\right )}{x} \, dx,x,a+b \arccos (c x)\right )}{b c} \\ & = -\frac {\cos \left (\frac {a}{b}\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \arccos (c x)\right )}{b c}+\frac {\sin \left (\frac {a}{b}\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \arccos (c x)\right )}{b c} \\ & = \frac {\operatorname {CosIntegral}\left (\frac {a+b \arccos (c x)}{b}\right ) \sin \left (\frac {a}{b}\right )}{b c}-\frac {\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \arccos (c x)}{b}\right )}{b c} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.05 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.85 \[ \int \frac {1}{a+b \arccos (c x)} \, dx=-\frac {-\operatorname {CosIntegral}\left (\frac {a}{b}+\arccos (c x)\right ) \sin \left (\frac {a}{b}\right )+\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a}{b}+\arccos (c x)\right )}{b c} \]

[In]

Integrate[(a + b*ArcCos[c*x])^(-1),x]

[Out]

-((-(CosIntegral[a/b + ArcCos[c*x]]*Sin[a/b]) + Cos[a/b]*SinIntegral[a/b + ArcCos[c*x]])/(b*c))

Maple [A] (verified)

Time = 0.49 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.91

method result size
derivativedivides \(\frac {-\frac {\operatorname {Si}\left (\arccos \left (c x \right )+\frac {a}{b}\right ) \cos \left (\frac {a}{b}\right )}{b}+\frac {\operatorname {Ci}\left (\arccos \left (c x \right )+\frac {a}{b}\right ) \sin \left (\frac {a}{b}\right )}{b}}{c}\) \(49\)
default \(\frac {-\frac {\operatorname {Si}\left (\arccos \left (c x \right )+\frac {a}{b}\right ) \cos \left (\frac {a}{b}\right )}{b}+\frac {\operatorname {Ci}\left (\arccos \left (c x \right )+\frac {a}{b}\right ) \sin \left (\frac {a}{b}\right )}{b}}{c}\) \(49\)

[In]

int(1/(a+b*arccos(c*x)),x,method=_RETURNVERBOSE)

[Out]

1/c*(-Si(arccos(c*x)+a/b)*cos(a/b)/b+Ci(arccos(c*x)+a/b)*sin(a/b)/b)

Fricas [F]

\[ \int \frac {1}{a+b \arccos (c x)} \, dx=\int { \frac {1}{b \arccos \left (c x\right ) + a} \,d x } \]

[In]

integrate(1/(a+b*arccos(c*x)),x, algorithm="fricas")

[Out]

integral(1/(b*arccos(c*x) + a), x)

Sympy [F]

\[ \int \frac {1}{a+b \arccos (c x)} \, dx=\int \frac {1}{a + b \operatorname {acos}{\left (c x \right )}}\, dx \]

[In]

integrate(1/(a+b*acos(c*x)),x)

[Out]

Integral(1/(a + b*acos(c*x)), x)

Maxima [F]

\[ \int \frac {1}{a+b \arccos (c x)} \, dx=\int { \frac {1}{b \arccos \left (c x\right ) + a} \,d x } \]

[In]

integrate(1/(a+b*arccos(c*x)),x, algorithm="maxima")

[Out]

integrate(1/(b*arccos(c*x) + a), x)

Giac [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.93 \[ \int \frac {1}{a+b \arccos (c x)} \, dx=\frac {\operatorname {Ci}\left (\frac {a}{b} + \arccos \left (c x\right )\right ) \sin \left (\frac {a}{b}\right )}{b c} - \frac {\cos \left (\frac {a}{b}\right ) \operatorname {Si}\left (\frac {a}{b} + \arccos \left (c x\right )\right )}{b c} \]

[In]

integrate(1/(a+b*arccos(c*x)),x, algorithm="giac")

[Out]

cos_integral(a/b + arccos(c*x))*sin(a/b)/(b*c) - cos(a/b)*sin_integral(a/b + arccos(c*x))/(b*c)

Mupad [F(-1)]

Timed out. \[ \int \frac {1}{a+b \arccos (c x)} \, dx=\int \frac {1}{a+b\,\mathrm {acos}\left (c\,x\right )} \,d x \]

[In]

int(1/(a + b*acos(c*x)),x)

[Out]

int(1/(a + b*acos(c*x)), x)